# Rounded Mean help (to the tenth place)

**URL:** <https://cl.desmos.com/t/rounded-mean-help-to-the-tenth-place/3289>\
**Category:** Questions\
**Tags:** aggregate\
**Created:** [May 16, 2021, 12:56pm UTC](https://cl.desmos.com/t/rounded-mean-help-to-the-tenth-place/3289 "2021-05-16T12:56:12Z")\
**Posts on this page:** 1\
**Showing post:** 3

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**Author:** ![Aethir](https://yyz1.discourse-cdn.com/flex031/user_avatar/cl.desmos.com/aethir/32/2767_2.png) [@Aethir](https://cl.desmos.com/u/Aethir)\
**Post date:** [May 16, 2021, 2:28pm UTC](https://cl.desmos.com/t/rounded-mean-help-to-the-tenth-place/3289/3 "2021-05-16T14:28:31Z")

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Alternately:

> [@Rounding & Truncating](https://cl.desmos.com/t/rounding-truncating/1035):
>
> Searching the forum, I found a way to round a value to 2 decimal places (useful in CL documentation?) rounded\_value = simpleFunction("\operatorname{round}(k,2)",“k”).evaluateAt(value) Using this I can also round to an integer by setting the number of decimal places to zero but is there a better way? Also, is there an operator for ‘truncate’? I tried that and ‘trunc’ in the above but no success.

Just pass the number of decimal places you want the number rounded to as another argument.

round(number,digits)

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