How to check when simplifying expressions

[Daniel_Grubbs]

You can use simpleFunction() to turn an expression into a function, then evaluate as you would an equation. Is that what you mean? If you want to see that it’s simplified, you’ll want to find some threads that discuss countNumberUsage.

Here’s one:

Check Algebraic Expression Answer

Thanks. I’m not actually part of the Desmos team, just a user who enjoys the coding puzzles and helping people out. First, you can use countNumberUsage to identify specific expressions. (See post 6 in this thread). Second, if you have equivalent expressions, you could just create a function that is the difference of the two. Being equivalent, any value of x should evaluate to zero. Say you want a student to simplify exp1 in a math input. exp1=`4x-2x+5` f= simpleFunction("${exp1} - (${this.la…