I would like for my answer to not only accept 6/3 but also 2. What part of the code do I need to change?
correct: correct
correct = slope1.submitted and slope1.latex = “\frac{6}{3}”
suffix: when slope1.script.correct and slope1.submitted “
”
when slope1.submitted “
”
otherwise “”
Here is the activity: [Copy of] AG1 Identifying Slopes and y-intercepts • Activity Builder by Desmos
Something along the lines of
correct = slope1.submitted and (slope1.latex="\frac{6}{3}" or slope1.numericValue=2)
should do the trick - this will allow any answer equivalent to 2. (In fact making the LaTeX comparison redundant).
You could equally use (slope1.latex="\frac{6}{3}" or slope1.latex="2") if you wish to force only those two answers.
thank you, very easy fix! What would I change if it was a repeating fraction though? Like the slope was 2/3 and they put 6/4.
I mean 4/6, sorry long day
Then you can use the numericValue function… so slope1.numericValue=numericValue("2/3") should accept any equivalent to 2/3 - including, I just discovered, manually typing 0.6666666666666666 with at least 16 sixes!
Thank you so much, can I also ask you another question that you might be able to help me with. So they are writing equations and they could write y=4x+1 or y=16/4x+1 and technically they are both correct. My last coding just has the latex for one of them. How would I adjust that?
This is what I have for one of them:
correct: correct
disableEvaluation: true
correct = e1.submitted and e1.latex = “y=\frac{6}{3}x+2”
suffix: when e1.script.correct and e1.submitted “”
when e1.submitted""
otherwise “”
For linear functions like that you can use the xyLine function… so along the lines of
line=xyLine(e1.latex)
correct = e1.submitted and line.slope=4 and line.yIntercept=1
You may want to add additional checks if you want it specifically in y=mx+c form, because the code above will accept any equivalent variation - y-4x=1, x=(y-1)/4, etc. etc.
Thank you so much for all of your help
For non-terminating decimals, numericValue does not always yield equivalent (something to do with how it’s calculated). simpleFunction is more stable in this respect:
check= simpleFunction(slope1.latex).evaluateAt(0) = simpleFunction(`2/3`).evaluateAt(0)
However, you can also use inequalities in a few different ways:
check= slope1.numericValue>0.33 and slope1.numericValue<0.34
or
check= numericValue(`\abs( (${slope1.numericValue}) - \frac{2}{3} )`)<=0.01
I like to use the rounding operator.
correct= when numericValue("\\operatorname{round}\\left(${input.numericValue},2\\right)")=numericValue("\\operatorname{round}\\left(\frac{2}{3},2\\right)")
I knew I was missing one. 